Given a collection of integers that might contain duplicates, nums, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If nums = [1,2,2]
, a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
public class Solution { public List<List<Integer>> subsetsWithDup(int[] nums) { List<List<Integer>> res = new ArrayList<List<Integer>>(); if (nums.length<=0 || nums==null) { return res; } Arrays.sort(nums); ArrayList<Integer> list = new ArrayList<Integer>(); for (int i = 1; i <= nums.length; i++) { dfs(nums, 0, i, list, res); } res.add(new ArrayList<Integer>()); return res; } private void dfs(int[] arr, int start, int len, ArrayList<Integer> list, List<List<Integer>> res) { if (list.size() == len) { if (!res.contains(list)) { res.add(new ArrayList<Integer>(list)); } return; } for (int i = start; i < arr.length; i++) { list.add(arr[i]); dfs(arr, i+1, len, list, res); list.remove(list.size()-1); } } }
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