Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode sortedArrayToBST(int[] nums) { return solve(nums, 0, nums.length-1); } private TreeNode solve(int[] nums, int s, int e) { if (s > e) { return null; } int mid = (s+e)/2; TreeNode root = new TreeNode(nums[mid]); root.left = solve(nums, s, mid-1); root.right = solve(nums, mid+1, e); return root; } }
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