Given a string s, partition s such that every substring of the partition is a palindrome.
Return the minimum cuts needed for a palindrome partitioning of s.
For example, given s = "aab"
,
Return 1
since the palindrome partitioning ["aa","b"]
could be produced using 1 cut.
public class Solution { public int minCut(String s) { int res = 0; int len = s.length(); boolean[][] matrix = new boolean[len][len]; int cuts[] = new int[len+1]; if (s == null || s.length() == 0) { return res; } for (int i = 0; i < len; ++i) { cuts[i] = len - i; } for (int i = len-1; i >= 0; i--) { for (int j = i; j < len; j++) { if (((s.charAt(j)==s.charAt(i)) && j-i<2) || (s.charAt(i) == s.charAt(j) && matrix[i+1][j-1])) { matrix[i][j] = true; cuts[i] = Math.min(cuts[i], cuts[j+1]+1); } } } res = cuts[0] - 1; return res; } }
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